![]() (Vote for please, I'm just illustrating how to clearly explain - I hope - what you want to achieve, sample data, etc). WHERE string_a LIKE ANY (SELECT '%'||candidate_str||'%' FROM tableB) If so, shamelessly stealing excellent suggestion, you would use: SELECT string_a bork doesn't match any substring so it is not found. There is no need to show the substring(s) that matched. I want the result set: the manual is greatīecause the manual is great has man and great in it and because chicken chicken chicken has chicken in it. ('the manual is great'), ('Chicken chicken chicken'), ('bork') Use the LIKE operator The LIKE operator is used in SQL to match a string with a pattern. Given: CREATE TABLE tableA (string_a text) In SQL Server, there are 3 main ways to check if a string contains a substring: 1. The second argument is the delimiter (a comma), and the third is the position of the desired element. The first is the name of the fieldin this case, drugsinreceipt. ![]() The PostgreSQL splitpart function takes three arguments. Syntax: SUBSTRING ( string, startposition, length ) Let’s analyze the above syntax: The string is a string whose data type is char, varchar, text, etc. Sn is a substring of Sa.Ī simple example to show what I mean (hint, hint): Here is the query we’ll use: SELECT splitpart (drugsinreceipt, ',',1) as firstmedicine. Discuss Courses Practice In PostgreSQL, the substring function is used to extract a substring from a string. Sn from table B to find out if any of the other strings in S1. I'm going to take a wild stab in the dark and assume you mean that you want to match a string Sa from table A against one or more other strings S1. The string concatenation operator () will accept non-string input, so long as at least one input is of string type, as shown in Table 9.9.For other cases, inserting an explicit coercion to text can be used to have non-string input accepted. How to find substring using results of subquery?ĬONSTRAINT uchastki_pkey PRIMARY KEY (fid),ĬONSTRAINT enforce_dims_the_geom CHECK (st_ndims(the_geom) = 2) I have a table and i want to find a string in one row (character varying datatype) of this table using substring (character varying datatype) returned by subquery: SELECT uchastki.kadnumīut get a error ERROR: more than one row returned by a subquery used as an expression
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |